Regarding the chamber pressure method of measuring mixes, you would first calculate the correct amount of propane for say a 10x mix:
Vp = ((100/.958)-100)*10
Vp = 43.84 in^3
to find the pressure in the chamber after adding the propane, you figure out how much volume you are adding, and multiply that percentage by the pressure in the chamber (14.7 psi)
Pp = (43.84/100)*(14.7)
Pp = 6.44 psi
The next step is what is missing. From what I've seen it is assumed that you can now pump up the chamber to 132.3 psi (14.7*9), but this assumption neglects the volume of propane you just added. In order to get the correct mix, you must add in the pressure of the propane, thus upping the pressure to 138.7 psi. I know this is a minor error at small mixes, but with a 10x mix as above, that's over 6 psi.
Just thought I'd clarify, because I know this was bugging me, so it might have confused others as well
