What is a good ratio to follow as far as barrel to chamber size goes? Length wise and diameter wise. Thanks!
Ratios on my gun:
Length-1:2
Width-1:3
Any problems?
Ratios
These are useless, C:B ratios are always expressed as volume to volume. Diameter has very little effect in most cases.
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- CannonCreator
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Here bro you need this. After you get your CB ratio off of this calc, you can ask this qustion
http://www.burntlatke.com/calc.html
Ude the link above, once your there select and download RatClac. It will give you more presice CB ratios, and it will show you the correct way to right it.
http://www.burntlatke.com/calc.html
Ude the link above, once your there select and download RatClac. It will give you more presice CB ratios, and it will show you the correct way to right it.
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- MrCrowley
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CannonCreator isn't that calculator for combustions not pneumatics?
I hear there is no perfect ratio in a pneumatic but there is a good guide-line that it should be in, though I forogt what it is and can't find it.
I hear there is no perfect ratio in a pneumatic but there is a good guide-line that it should be in, though I forogt what it is and can't find it.
Ratios for pneumatics depend on the pressure used. The higher the pressure, the larger the volume of the barrel should be for a given chamber size. At the pressures normally used, with a fixed chamber size, a .3:1 ratio can utilise most of the available power.
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0.3:1 ratio?
So my "Kandy Kain" isn't as inefficient as I thought it was.
So my "Kandy Kain" isn't as inefficient as I thought it was.
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DYI is a bit wrong since given the length to length ratio of the chamber and barrel, and the diameter ratios then volume ratios can be calculated. However, the normal way to express things is either as the volumes (or their ratio) or by giving the complete set of dimensions; length and width of both the chamber and barrel.
Of course, if you do it they way you did, you need to present the numbers in a manner that makes sense;
Did you mean;
from which the volume ratio can be calulated as;
(volume chamber)/(volume barrel) = (pi)(r<sub>chamber</sub><sup>2</sup>)(L<sub>chamber</sub>) //(pi)(r<sub>barrel</sub><sup>2</sup>)(L<sub>barrel</sub>)
canceling things gives;
(r<sub>chamber</sub><sup>2</sup>)(L<sub>chamber</sub>) / (r<sub>barrel</sub><sup>2</sup>)(L<sub>barrel</sub>)
Using the ratios in place of the actual r's and L's;
(3<sup>2</sup>)(1)/(1<sup>2</sup>)(2) = 9/2 = 4.5
Now, like MrCrowley said, the optimal ratio of a pneumatic depends entirely on what you are trying to optimize. For optimal use of the available energy in the chamber then the barrel should be fairly long and the C:B fairly small, approaching roughly 1:9 (0.11 ratio) for a 120 PSIG chamber pressure.
For optimal muzzle velocity for a fixed barrel length, the chamber should be as large as possible. The ratio might be 3:1 (3 ratio) or more.
Of course, if you do it they way you did, you need to present the numbers in a manner that makes sense;
Does that mean the barrel is twice the length of the chamber and the diameter of the barrel is 3x the diameter of the chamber? Dosn't sound very likely.Ratios on my gun:
Length-1:2
Width-1:3
Did you mean;
Code: Select all
chamber : barrel
length ratio 1 : 2
diameter ratio 3 : 1
(volume chamber)/(volume barrel) = (pi)(r<sub>chamber</sub><sup>2</sup>)(L<sub>chamber</sub>) //(pi)(r<sub>barrel</sub><sup>2</sup>)(L<sub>barrel</sub>)
canceling things gives;
(r<sub>chamber</sub><sup>2</sup>)(L<sub>chamber</sub>) / (r<sub>barrel</sub><sup>2</sup>)(L<sub>barrel</sub>)
Using the ratios in place of the actual r's and L's;
(3<sup>2</sup>)(1)/(1<sup>2</sup>)(2) = 9/2 = 4.5
Now, like MrCrowley said, the optimal ratio of a pneumatic depends entirely on what you are trying to optimize. For optimal use of the available energy in the chamber then the barrel should be fairly long and the C:B fairly small, approaching roughly 1:9 (0.11 ratio) for a 120 PSIG chamber pressure.
For optimal muzzle velocity for a fixed barrel length, the chamber should be as large as possible. The ratio might be 3:1 (3 ratio) or more.