Since i dont know much about combustion cannons, i was asking for good methods of measuring ratios i was looking at Wiki and i wanted to know
how you guyz figure out your ratios so i can use the same priciples to
measure my cannons preformance which i have no idea about.
So plz tell me how you guyz figure out your cannons ratio.
Calculating ratios
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mark.f
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I think he's talking about volumetric ratios.
And, since I'm tired of this question, I will answer with cool-looking equations:
In that case, V<sub>c</sub>/V<sub>b</sub>=k, where k equals some constant, which is your C:B ratio. To calculate this ratio, use the following process/formula:
Definition of volumetric C:B ratio
Chamber volume, form of volume of a cylinder
The volume of the barrel takes same form
Composition
Simplified formula for C:B ratio
Just plug values into the last equation for your C:B ratio.
And, I will end this post with the ever-present reply: SEARCH!
And, since I'm tired of this question, I will answer with cool-looking equations:
In that case, V<sub>c</sub>/V<sub>b</sub>=k, where k equals some constant, which is your C:B ratio. To calculate this ratio, use the following process/formula:
Definition of volumetric C:B ratio Chamber volume, form of volume of a cylinder The volume of the barrel takes same form Composition Simplified formula for C:B ratioJust plug values into the last equation for your C:B ratio.
And, I will end this post with the ever-present reply: SEARCH!
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jimmy101
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Another way to do CB ratio;
CB ratio = D<sub>c</sub><sup>2</sup> L<sub>c</sub> / D<sub>b</sub><sup>2</sup> L<sub>b</sub>
where
D<sub>c</sub> = diameter of the chamber
L<sub>c</sub> = length of the chamber
D<sub>b</sub> = diameter of the barrel
L<sub>b</sub> = length of the barrel
I'll leave it as an excercise for the reader to show that the fomula above is equivalent to markfh11q's equation;
CB ratio = r<sub>c</sub><sup>2</sup> L<sub>c</sub> / r<sub>b</sub><sup>2</sup> L<sub>b</sub>
CB ratio = D<sub>c</sub><sup>2</sup> L<sub>c</sub> / D<sub>b</sub><sup>2</sup> L<sub>b</sub>
where
D<sub>c</sub> = diameter of the chamber
L<sub>c</sub> = length of the chamber
D<sub>b</sub> = diameter of the barrel
L<sub>b</sub> = length of the barrel
I'll leave it as an excercise for the reader to show that the fomula above is equivalent to markfh11q's equation;
CB ratio = r<sub>c</sub><sup>2</sup> L<sub>c</sub> / r<sub>b</sub><sup>2</sup> L<sub>b</sub>
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mark.f
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Well, since radius is 1/2 diameter, you can multiply each D by 1/2, factor out these 1/2's, and they cancel to equal one. Since the constant 1/2 exists in the numerator and denominator, they cancel.
Yup. I guess that's for people who don't want to divide diameter in half to get radius.
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bigbob12345
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jimmy101
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Actually, it's for people who know that the area scales as the square of the diameter or the radius. Since pipe is sized in diameters there is no need to add two divisions to the problem. It is much easier to think of a 3" diameter chamber and a 1.5" diameter barrel using those numbers instead of 1.5" and 0.75".markfh11q wrote:
Well, since radius is 1/2 diameter, you can multiply each D by 1/2, factor out these 1/2's, and they cancel to equal one. Since the constant 1/2 exists in the numerator and denominator, they cancel.
Yup. I guess that's for people who don't want to divide diameter in half to get radius.
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mark.f
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Sometimes diameter is prettier than radius, (i.e. dividing 1.625 by two adds another decimal figure). I wasn't trying to be sarcastic, I just said that's another way to do it without dividing diameter in half to get radius. There the same because multiplying by 2/2 is the same as multiplying the whole equation by 1, and multiplying each radius by two yields the diameter, so they scale the same.
And, if we really wanted to simplify it some more, we could rewrite it as:
<div align="center">
</div>
Stop me! My photobucket's screaming!!!
And, if we really wanted to simplify it some more, we could rewrite it as:
<div align="center">
</div>Stop me! My photobucket's screaming!!!